And the challenge was to work out what the fewest numbers of moves was required to make a valid equation.

**delta_mike**spotted the obvious solution of moving the second I to the far right, giving I + X = XI (this is the one I tried originally).

**talismancer**came up with a slight variation on this as well.

Bonus marks to

**omgimsuchadork**for the inventive answer of moving the I to create I + XI ≠ X

One guy at work found yet another 1-move solution: I - XI = -X

Of course, this is a trick question and so none of those are correct. The correct answer is none, and bragging rights to

**the_s_guy**for spotting that.

The solution is to rotate the surface your matchsticks are on (or walk round to the other side of the table), giving X = IX + I which is 10 = 9 + 1 and so is correct.

I actually didn't solve this by working that out - I saw that I could do it with 1 move, mistakenly assumed that it wasn't a trick question (I should have known better by then), and so entered 1 as my answer. When the game rejected it I then entered 0, as if it takes less than 1 move then there's only one possible answer left.